Reversing an array

@anon98822045

I found an even more delightful solution that just uses the existing Iter.revRange() function with your Int.abs() suggestion. Teamwork makes the dream work :laughing:

do {
  let arr = [2,4,6,8,10];
  for (i in Iter.revRange(arr.size(), 1)) {
    Debug.print(debug_show(arr[Int.abs(i-1)]));
  };
};
// Output

10
8
6
4
2